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    <title>Document</title>
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    <button>send</button>
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            let content=document.querySelector('input').value;
            let xhr=new XMLHttpRequest;
            xhr.open('GET','http://127.0.0.1/WHSecondClass/2022.7.15/ajax_getrequest.php?name='+content);
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            xhr.onload=function(){
                let response=JSON.parse(xhr.responseText);
                if(response.code != 0){
                    console.log('网络开小差了')
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